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Asked by rohitraman1115 | 02 Jul, 2018, 09:43: PM
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torque = begin mathsize 12px style bold p with bold rightwards arrow on top bold cross times bold E with bold rightwards arrow on top space equals space p cross times E cross times sin theta space equals space q cross times d cross times E cross times sin theta space equals space q cross times 2 cross times 10 to the power of negative 2 end exponent cross times 10 to the power of 5 cross times 1 half space equals space 10 square root of 3 space................ left parenthesis 1 right parenthesis end style
In eqn.(1), q is charge in Coluomb, d is distance between charges in dipole, E is electric field and θ is angle between field direction and dipole.
 
from eqn.(1), we get,   q = √3 × 10-2 C
 
potential energy = begin mathsize 12px style negative bold space bold italic p bold times bold italic E space equals space p cross times E cross times cos theta space equals negative space q cross times d cross times E cross times cos theta space equals negative space square root of 3 space cross times 10 to the power of negative 2 end exponent cross times 2 cross times 10 to the power of negative 2 end exponent cross times 10 to the power of 5 cross times fraction numerator square root of 3 over denominator 2 end fraction space equals negative 30 space J end style
Answered by Thiyagarajan K | 03 Jul, 2018, 10:09: AM

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