JEE Class main Answered
Solve it using graph
Asked by vishakhachandan026 | 10 May, 2019, 20:20: PM
Expert Answer
|e|x - β| - α| = 2
e|x - β| - α = ±2
e|x - β| = α ± 2
α + 2 > 0 and α - 2 > 0 i. e. α > 2
α 
(2, ∞)
(2, ∞)e|x - β| i. e. x - β 
R then β R
R then β R
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