Sir, you had given the answer that The range of f(x)=1+x^2+x^3 is the set of all values that f(x) can take .that is every element of codomain is related to element of domain is called Range.my question is that “At what value of x , f(x) =0 means Does 0Îrange has preimage (x) in the domain ? “ Because you had written the range is -∞ To ∞ and 0Î(-∞,∞)
Sir, you had given the answer that The range of f(x)=1+x^2+x^3 is the set of all values that f(x) can take .that is every element of codomain is related to element of domain is called Range.my question is that “At what value of x , f(x) =0 means Does 0Îrange has preimage (x) in the domain ? “ Because you had written the range is -∞ To ∞ and 0Î(-∞,∞)
Asked by Kalyanrao Chavan
| 2nd Jun, 2014,
06:25: PM
Expert Answer:
Let us observe the following graph:
The given graph passes through the y-axis at x=0 and the value of the function at x=0 is y=1.
Similarly, it passes through the x-axis at y=0 and the value of x is approximately, x = -1.45.
Thus, at x = -1.45, f(x) = 0.
I hope i have cleared your doubt to some extent.
If, not, please post your query once again.
Answered by Vimala Ramamurthy
| 3rd Jun, 2014,
09:44: AM
Application Videos
Concept Videos
- confuse
- Let A and B be non empty sets and f is a mapping from A×B to B×A such that (a,b)=(b,a), then 'f' is
- Check surjectivity. Plzz
- 2018, 25, Maths,find the set of elements.
- show that the relation R on R defined as R={(a,b):a<_b } is reflexive, transitive but not symmetric Chapter: Relations and functions
- et f R--> R be defined by f(x) = 3x -4, then find f^-1(x
- Define function.
- Define bijective function.
- Let
defined by f(1) = f(2) = 1 and f(x) = x – 1 for x > 2. Show that f is onto but not one-one.
- Check the function
given by
is one-one or not.
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change