Check surjectivity. Plzz

Asked by prakriti12oct | 6th Jul, 2019, 12:40: AM

Expert Answer:

f(x) = x3
First we will check injectivity of the function.
If f(x1) = f(x2)
begin mathsize 16px style straight x subscript 1 superscript 3 space equals straight x subscript 2 superscript 3
straight x subscript 1 equals straight x subscript 2 end style
Hence, function is injective.
Let us check for surjectivity.
f(x) = y = x3
then x = begin mathsize 16px style cube root of straight y end style
Hence given function is injective and surjective.

Answered by Sneha shidid | 8th Jul, 2019, 04:51: PM