CBSE Class 12-science Answered
Sir question attatched
Question no. 10
Asked by shobhit | 14 May, 2018, 08:54: AM
Expert Answer
circumfrential displacement S of P as a function of time t is given by
S(t) = t2 + 5 ;
tangential speed of p ; (dS/dt) = v = 2t m/s
tangential acceleration of P ; (d2S/dt2) = at = 2 m/s2 ;
Radial acceleration of P at t = 5(√3/√10) ; ar = v2/r = (4×25×3)/(10×20) = 1.5 m/s2
total acceleration a is given by
Answered by Thiyagarajan K | 14 May, 2018, 03:03: PM
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