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Sir plz solve it step by step
Asked by vishakhachandan026 | 26 Jul, 2019, 15:05: PM
Expert Answer
Given:
Volume of mixture of gases = 28 L
Pressure = 1atm
Temperature = 273 K
Using gas equation,
PV = nRT
let C2H4 = x
C2H6 = y
x + y = 1.25 mol ....(1)
The mixture of gases reacts with O2
Mixture completely reacts with 128 gm of O2
Now,
From eq (1) and (2)
y= 0.5 mol
Mole fraction of C2H4
So mole fraction of C2H4 = 1- 0.4
= 0.6
Answered by Varsha | 26 Jul, 2019, 17:34: PM
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