Request a call back

Join NOW to get access to exclusive study material for best results

JEE Class main Answered

Sir plz solve it step by step ,U may leave part (b) but plz solve explaining part(a)
question image
Asked by vishakhachandan026 | 08 Aug, 2019, 10:21: AM
answered-by-expert Expert Answer
Given:
 
For NO,
 
Volume = 0.25 L
 
Pressure = 800 torr
 
            equals space 800 over 760

equals 1.05 space atm
 
 
temperature = 220 K
 
By using gas equation, no. of moles can be calculated as,
 
PV = nRT
 
 
straight n equals PV over RT

space equals fraction numerator 1.05 cross times 0.25 over denominator 0.0821 cross times 220 end fraction

space straight n equals 0.0145 space mol
 
 
For O2 
For NO,
 
Volume = 0.1 L
 
Pressure = 600 torr
 
            equals space 600 over 760

equals 0.79 space atm
 
 
temperature = 220 K
By using gas equation, no. of moles can be calculated as,
 
PV= nRT
 
straight n equals PV over RT

space space equals fraction numerator 0.79 cross times 0.1 over denominator 0.0821 cross times 220 end fraction

straight n equals space 0.00437 space mol
 
The reaction to form N2O4 
 
2NO + O2 → N2O4 
 
2 mole of NO reacts with 1 mole of  O2 
 
so, 0.00437 mole of  O2 will require 
 
fraction numerator space 0.00437 cross times 2 over denominator 1 end fraction

equals 0.00874 space mol space of space NO
 
(a)
 
Excess of NO is : 0.0.145 - 0.00874 = 0.00578 mole of NO
 
Now aain by using gas law we can calculate pressure,
 
PV = nRT
 
straight P equals nRT over straight V

space space space space equals fraction numerator 0.00576 cross times 0.00821 cross times 220 over denominator open parentheses 0.25 plus 0.1 close parentheses end fraction

straight P equals 0.299 space atm
 
(b) From equation,
 
2 mole of NO gives 1 mole of N2O4 
 
so 0.00874 mole of NO will give,
 
equals fraction numerator 0.00874 cross times 1 over denominator 2 end fraction

equals 0.00437 space mole space of space straight N subscript 2 straight O subscript 4
 
Molar mass of N2O4 = 92g/mol
 
Mass of N2O4 = 92×0.00437
 
                    = 0.402 gm.
 
 
Answered by Varsha | 08 Aug, 2019, 12:52: PM
JEE main - Chemistry
Asked by vishakhachandan026 | 08 Aug, 2019, 10:21: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Chemistry
Asked by ashutosharnold1998 | 08 Aug, 2019, 12:11: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Chemistry
Asked by vishakhachandan026 | 04 Jul, 2019, 02:59: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Chemistry
Asked by Anish | 09 Jan, 2019, 11:33: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×