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Sir pls solve the following.
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Asked by rsudipto | 01 Jan, 2019, 10:20: AM
answered-by-expert Expert Answer
begin mathsize 12px style integral fraction numerator cos e c squared x minus 2005 over denominator cos to the power of 2005 x end fraction d x space equals space integral fraction numerator cos begin display style e end style begin display style begin display style c end style squared end style begin display style x end style begin display style space end style begin display style d end style begin display style x end style over denominator begin display style cos to the power of 2005 end style begin display style x end style end fraction space minus integral fraction numerator 2005 over denominator cos to the power of 2005 x end fraction space equals space I subscript 1 minus I subscript 2 I subscript 1 space equals space integral fraction numerator begin display style cos e c squared x space d x end style over denominator begin display style cos to the power of 2005 x end style end fraction space equals space minus integral fraction numerator begin display style d left parenthesis c o t space x right parenthesis end style over denominator begin display style cos to the power of 2005 x end style end fraction space equals space minus fraction numerator c o t space x over denominator cos to the power of 2005 x end fraction plus integral c o t space x space left parenthesis negative 2005 right parenthesis space cos to the power of negative 2006 end exponent x space left parenthesis negative sin space x right parenthesis space d x space equals negative fraction numerator begin display style c o t space x end style over denominator begin display style cos to the power of 2005 x end style end fraction plus integral fraction numerator 2005 over denominator begin display style cos to the power of 2005 end style begin display style x end style end fraction d x space plus C I subscript 1 space equals negative fraction numerator begin display style c o t space x end style over denominator begin display style cos to the power of 2005 x end style end fraction plus I subscript 2 plus C I subscript 1 space space minus space I subscript 2 equals space minus fraction numerator begin display style c o t space x end style over denominator begin display style cos to the power of 2005 x end style end fraction plus C end style
Hence the answer : (D) none of these
Answered by Thiyagarajan K | 01 Jan, 2019, 15:07: PM

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