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CBSE Class 12-science Answered

Sir 

Pl solve question no-3

Asked by shobhit | 14 May, 2018, 08:52: AM
Expert Answer
Figure shows the forces acting on the mass and resolved components related to this question. As shown in figure resolved component of weight (mg sinθ) and centripetal force ( mω2r ) acting against the frictional force (μ mg cosθ ) . μ is the friction coefficient.
 
mg sinθ + 2r = μ mg cosθ;
 
Hence μ = tanθ + ω2r /(g cosθ) 
 
substitute the values of θ, ω and r in the above relation and get the value of μ
Answered by Thiyagarajan K | 14 May, 2018, 02:29: PM
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