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CBSE Class 12-science Answered

Sir  Pl solve question no-3
question image
Asked by shobhit | 14 May, 2018, 08:52: AM
answered-by-expert Expert Answer
Figure shows the forces acting on the mass and resolved components related to this question. As shown in figure resolved component of weight (mg sinθ) and centripetal force ( mω2r ) acting against the frictional force (μ mg cosθ ) . μ is the friction coefficient.
 
mg sinθ + 2r = μ mg cosθ;
 
Hence μ = tanθ + ω2r /(g cosθ) 
 
substitute the values of θ, ω and r in the above relation and get the value of μ
Answered by Thiyagarajan K | 14 May, 2018, 02:29: PM
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