CBSE Class 10 Answered
sinA-cosA-1/sinA+cosA-1=1/secA-tanA

Asked by skailas803 | 05 Jan, 2023, 11:37: PM
Let us use the symbol
S = sinA and C = cosA



( To simplify above expression , we used in numerator " cos2A- 1 = - sin2A " . i.e., C2 - 1 = S2 "
similarly in denominator , we used " sin2A- 1 = - cos2A " . i.e., S2 -1 = -C2 )
Hence we get

If we divide the numerator and denominator of RHS by sinA , we get

( We get RHS of above expression as given above .
we will not get RHS as given in the question , i.e., RHS ≠ 

I cross checked the answer using EXCEL )
Answered by Thiyagarajan K | 06 Jan, 2023, 11:54: AM
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