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sinA-cosA-1/sinA+cosA-1=1/secA-tanA
Asked by skailas803 | 05 Jan, 2023, 11:37: PM
Let us use the symbol

S = sinA   and   C = cosA

( To simplify above expression , we used in numerator   " cos2A- 1 = - sin2A  "  . i.e., C2 - 1 = S2 "

similarly in denominator  , we used  " sin2A- 1 = - cos2A  "  . i.e., S2 -1 = -C2  )

Hence we get

If we divide the numerator and denominator of RHS by sinA , we get

( We get RHS of above expression as given above .

we will not get RHS as given in the question , i.e., RHS ≠
I cross checked the answer using EXCEL )

Answered by Thiyagarajan K | 06 Jan, 2023, 11:54: AM

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