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CBSE Class 10 Answered

Sec 41 Sin 49 Cosec 41-fraction numerator 2 over denominator square root of 3 end fractionTan 20 Tan 60 Tan 70-3 left parenthesis C o s squared 45 minus S i n squared 90 right parenthesis
Asked by adalroshan2464 | 20 Aug, 2019, 04:31: PM
answered-by-expert Expert Answer
Incomplete question:
It should be..
sec space 41 space sin space 49 space plus space cos space 49 space cosec space 41 space minus space fraction numerator 2 over denominator square root of 3 end fraction tan space 20 space tan space 60 space tan space 70 space minus space 3 left parenthesis cos squared 45 space minus space sin squared space 90 space right parenthesis
equals sec space 41 space sin space open parentheses 90 minus 41 close parentheses space plus space cos space 49 space cosec space open parentheses 90 minus 49 close parentheses space minus space fraction numerator 2 over denominator square root of 3 end fraction tan space 20 space tan space 60 space tan space open parentheses 90 minus 20 close parentheses space minus space 3 left parenthesis cos squared 45 space minus space sin squared space 90 space right parenthesis
equals sec space 41 space cos space 41 space plus space cos space 49 space sec space 49 space minus space fraction numerator 2 over denominator square root of 3 end fraction tan space 20 space tan space 60 space cot space 20 space minus space 3 left parenthesis cos squared 45 space minus space sin squared space 90 space right parenthesis
equals 1 space plus space 1 space minus space fraction numerator 2 over denominator square root of 3 end fraction cross times square root of 3 space minus space 3 open parentheses negative 1 half close parentheses
equals 3 over 2
Answered by Arun | 21 Aug, 2019, 10:03: AM
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