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ICSE Class 10 Answered

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Sintheta-2Sintheta
___________          = tantheta
2Cos^2theta -Cos theta
 
Cos A /1-tanA -Sin^2A/CosA -Sin A =Sin A +Cos A
 
(SecA-CosecA)(1+tanA+CotA)=tanA SecA -CotA CosecA
 
tan^2theta/tan^2theta -1  +Cosec^2theta / SEc^2theta -Cosec^2theta  = 1/Sin^2theta  - Cos^2theta
 
Eliminate theta in the equation
Cottheta +Costheta =m  , Cot theta - Costheta  =n
Asked by tejvarun | 15 Jun, 2017, 06:03: PM
answered-by-expert Expert Answer
Trigonometric Identities
 
begin mathsize 16px style Please space check space your space question colon LHS equals fraction numerator sinθ minus 2 sin cubed straight theta over denominator 2 cos cubed straight theta minus cosθ end fraction equals fraction numerator sinθ open square brackets 1 minus 2 sin squared straight theta close square brackets over denominator cosθ open square brackets 2 cos squared straight theta minus 1 close square brackets end fraction equals fraction numerator sinθ open square brackets 1 minus 2 open parentheses 1 minus cos squared straight theta close parentheses close square brackets over denominator cosθ open square brackets 2 cos squared straight theta minus 1 close square brackets end fraction equals fraction numerator sinθ open square brackets 2 cos squared straight theta minus 1 close square brackets over denominator cosθ open square brackets 2 cos squared straight theta minus 1 close square brackets end fraction equals tan space straight theta Note colon Please space post space one space query space at space straight a space time end style
Answered by Rashmi Khot | 16 Jun, 2017, 09:35: AM

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