Asked by arindeep.singh | 26th Sep, 2020, 10:39: AM
Q: Does there exist a quadratic equation whose coefficients are all distinct irrationals but both the roots are rationals? Why?
Yes, it is possible that a quadratic equation with distinct irrational coefficients have rational roots.
It is because, the roots are rational if the discriminant is a perfect square. So, it depends upon the discriminant and not on the coefficients.
Here is an example:
Answered by Renu Varma | 28th Sep, 2020, 11:00: AM
- Find the zeroes and verify the relationship between the zeroes and the its coefficient. X2 -2x - 8 = 0
- if alpha + beta are zeroes of the polynomial 2x^2-5x+7 then the value of alpha^-1 + Beta ^-1
- The value of k for which equation 9x2+8xk+8=0 has equal roots is:
- The positive value of ‘k’ for which x2+kx+64=0 and x2-8x+k=0 will both have real roots is a) 8 b) 4 c) 12 d) 16
- What's the answer for this question?
- X Squire+45x+765=0
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