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Question Asked by arindeep.singh | 18 Aug, 2020, 02:35: PM Expert Answer

It is given that sin B = sin Q

Clearly, since B and Q are acute angles, angle B = angle Q.

(As sine of two acute angles will be equal if and only if they are both equal)

You can prove this also by considering a right triangle ABQ.

Since, B and Q are acute angles, angle B is right angle.

Then, sinQ = AB/AQ

sin B = BQ/ AQ

Now, sin B = sin Q implies, AB = BQ

This gives angle B = angleQ

Answered by Renu Varma | 19 Aug, 2020, 11:39: AM

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