ques

Asked by nishac | 28th Feb, 2010, 10:12: AM

Expert Answer:

Join A and Q, the midpoint of BC.

In ACQ,

AQ2 = AC2 + CQ2          ... Pythagorus's theorem

CQ = BC/2            .... CQ = QB        given

AQ2 = AC2 + (BC/2)2  

AQ2 = AC2 + BC2/4  

4AQ2 = 4AC2 + BC2 ...... multiply both sides by 4

Similary in BCP, we can show that,

4BP2 = 4BC2 + AC2

regards,

Team,

TopperLearning.

Answered by  | 28th Feb, 2010, 11:23: AM

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