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Q5 in the attached picture.Please help.I am getting any clear concept from this question.
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Asked by Sanjeev | 20 Feb, 2018, 22:05: PM
answered-by-expert Expert Answer
begin mathsize 16px style Given colon space straight I space is space the space incentrte space of space straight a space circle comma space angle straight P equals 70 degree comma space angle PQR equals 54 degree Find colon space angle SPR comma space angle IPR comma space angle SIR Proof colon angle straight P equals 70 degree angle IPQ equals angle IPR space space space space space space space space space space space space space space space space space space space space space PI space is space angle space bisector space of space angle IPQ space and space angle IPR angle IPR equals 35 degree angle SPR plus angle RPI plus angle IPQ equals 70 degree angle PQR equals 54 degree angle PQS equals angle RQS equals 27 degree space space space space space space space space space space space space space space space space space QI space is space bisector space of space angle straight Q Arc space space SR equals 27 degree cross times 2 equals 54 degree angle SPR equals fraction numerator arc space SR over denominator 2 end fraction equals 27 degree angle SIR equals fraction numerator arc space SR over denominator 2 end fraction equals 27 degree end style
Answered by Sneha shidid | 21 Feb, 2018, 17:13: PM

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Q5 in the attached picture.Please help.I am getting any clear concept from this question.
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Asked by Sanjeev | 20 Feb, 2018, 22:05: PM
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