Ask a Doubt
Request a call back

Join NOW to get access to exclusive study material for best results

JEE Class main Answered

Q) An open bulb containing air at 19 degree Celsius was cooled to a certain temperature at which the number of moles of gaseous molecules increased by 25% what is the final temperature?
Asked by Anish | 08 Jan, 2019, 23:22: PM
answered-by-expert Expert Answer
Let,
 
Pressure in bulb = P1 
 
Volume of air = V
 
Initial temperature = T1 = 19+273 
 
                                    =292 K
 
Final temperature = T2 
 
Initial moles = n1 
 
Final moles = n2 
 
We have,
 
n2 = 1.25n1 
 
Using ideal gas equation,
 
 
PV equals space nRT Initially comma PV equals space straight n subscript 1 RT subscript 1 Finally comma PV equals space straight n subscript 2 RT subscript 2 therefore space straight n subscript 1 straight T subscript 1 space end subscript space equals space straight n subscript 2 straight T subscript 2 straight T subscript 2 space space end subscript space equals space fraction numerator space straight n subscript 1 straight T subscript 1 space end subscript space over denominator space straight n subscript 2 end fraction space space space space space space equals space fraction numerator up diagonal strike space straight n subscript 1 end strike cross times 292 over denominator 1.25 space space up diagonal strike straight n subscript 1 end strike end fraction straight T subscript 2 space space end subscript space equals space 233.6 space straight K
 
T2 = 233.6 K = 233.6 − 273
 
     = −39.6 °C
 
 
The final temperature is −39.6 °C
 
Answered by Varsha | 09 Jan, 2019, 15:06: PM

Application Videos

Concept Videos

Multiple Choice Questions Practice Test
Answered Unanswered My Questions My Answers
JEE main - Chemistry
please give me the answer of this question
question image
Asked by ruchisharmatbn | 06 Apr, 2024, 08:42: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Chemistry
A vertical hollow cylinder of height 152 cm is fitted with a weightless piston. The lower half is filled with an ideal gas and the upper half with mercury. The cylinder at 300 K is now heated, so that 1 th 4 of the mercury comes out. Find the temperature at which it will happen assuming thermal expansion of Hg to be negligible (1) 340 K (3) 328.12 K (2) 330.6 K (4) 322.2 K
Asked by arjuns94037 | 07 Jan, 2024, 12:43: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Chemistry
Sir plz solve it step by step ,U may leave part (b) but plz solve explaining part(a)
question image
Asked by vishakhachandan026 | 08 Aug, 2019, 10:21: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Chemistry
Why joule thomson coefficient for ideal gas is zero?
Asked by ashutosharnold1998 | 08 Aug, 2019, 00:11: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Chemistry
Which is correct graph for charle's law ,when the curve is plotted at .821 atm pressure for 10 mole idmolegas..sir plz do step by step
question image
Asked by vishakhachandan026 | 04 Jul, 2019, 14:59: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Chemistry
  Question: in a crystalline solid of XY3 cubic closed packed arrangement for its element Y,,,, X occupies.... ? Answer: 33% OCTAHEDRAL VOIDS.  how was this worked out? not the math necessarily,, but the voids occupied by X being OCTAHEDRAL and not TETRAHEDRAL. i don’t understand this part. i’d really appreciate it if someone could walk me through the logic here. thanks.
Asked by astutijoshi | 03 Jun, 2019, 17:12: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Chemistry
Q)There are 201 equidistant rows of spectators sitting in a hall A magician releases laughing gas n20 from the front and tear gas from the rear of the hall simultaneously. Which row spectators will have a tendency to smile and weep simultaneously. Molar mass of tear gas is 176.
Asked by Anish | 14 Mar, 2019, 11:14: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Chemistry
If silver atom occupy at centre, gold occupy body centre and lattice is CCP constituted by copper the formula of alloy will be
Asked by inbasri224 | 23 Feb, 2019, 23:48: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Chemistry
Q) The density of a mixture of O2 and N2 at STP is 1.3g/lit. Calculate the the partial pressure of O2.
Asked by Anish | 09 Jan, 2019, 23:33: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Chemistry
Q) An open bulb containing air at 19 degree Celsius was cooled to a certain temperature at which the number of moles of gaseous molecules increased by 25% what is the final temperature?
Asked by Anish | 08 Jan, 2019, 23:22: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
My Class Videos Tests ₹ Plans Ask a Doubt