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Q)A long rectangular box is filled with Cl2 (atomic mass=35.45) which is known to contain only Cl35 and Cl37. If the box can be divided into a partition and the two types of chlorine molecule are put into two compartments respectively. Calculate where should partition to be made if pressure on both sides is to be same? The ratio of pressure to original pressure is 1/x. So, the value of x is?
Asked by Anish | 08 Jan, 2019, 23:32: PM
answered-by-expert Expert Answer
Let us consider in the mixture,
The mole of Cl(35) = n1
The mole of Cl(37) = n2
 
Average molar mass = fraction numerator 35 cross times straight n subscript 1 plus 37 cross times straight n subscript 2 over denominator straight n subscript 1 plus straight n subscript 2 end fraction
 
35.45 space equals space fraction numerator 35 cross times straight n subscript 1 plus 37 cross times straight n subscript 2 over denominator straight n subscript 1 plus straight n subscript 2 end fraction

straight n subscript 1 over straight n subscript 2 space equals space 3.44
 
PV1=n1RT      PV2=n2RT
 
straight v subscript 1 over straight v subscript 2 space equals space straight n subscript 1 over straight n subscript 2
At constant P and T
 
The number of moles α Volume of gas
 
Therefore, the partition should be made in the volume ratio of 3.44:1.
 
Also, as we found that the pressure at this condition is the same as the original condition since the volume of the box and the number of mole along with temperature are constant.
 
So, the value of x should be 1.
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