Prove that the perpendicular at the point of contact to tangent to a circle passes through centre.
Asked by | 10th Mar, 2008, 03:12: PM
line l is tgt to the circleat P. O is the centre of the circle.OP=radius of the circle.If we hav some points Q1,Q2 etc. on l then we find that OP is the shorter distance from O in comparison to the distance OQ!,OQ2,etc. There fore OP is perpendicular to l. Hence the perpendicular OP drawn to the tangentline at P passes through the centre O of the circle.
Answered by | 16th Apr, 2008, 01:31: PM
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