prove that if a body is thrown vertically upwards the time of ascent is equal to the time of descent

Asked by  | 8th Sep, 2012, 08:18: AM

Expert Answer:

let the velocity at the time of throwing be U
thus the time for the velocity to become 0 at the highest point of flight.
Thus by first equation of motion thus t1 = U/g
Height attained, H = U2/2g          uisng the second equation of motion
Now at the time the time of descent,
time taken for the ball to come down will be:
t22 = 2H/g            using the third equation of motion
thus t2 = (U/g)2
clearly t1 = t2

Answered by  | 8th Sep, 2012, 04:54: PM

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