CBSE Class 12-science Answered
Point charges +q,+q,-q are placed at the corner of A,B,C respectively of an equilateral triangle ABC, The resultant force on -q placed at C
Asked by rite2raji | 02 Feb, 2020, 09:40: AM
Expert Answer
Let the side of triangle be a . At vertex A and B , charge +q is placed.
At vertex C, charge -q is placed.
Force F1 on charge -q due to the charge +q at A = -q2 / [ (4πεo) a2 ]
Force F2 on charge -q due to the charge +q at B = -q2 / [ (4πεo) a2 ]
Resultant of the force FR = ( - 2 q2 cos30 ) / [ (4πεo) a2 ] = ( - √3 q2 ) / [ (4πεo) a2 ]
( forces F1 and F2 are resolved into two components, i.e., one component parallel to AB and other one perpendicular to AB .
Parallel components of each force cancel each other.
While perpendiclar components are getting added together to give resultant FR )
Answered by Thiyagarajan K | 02 Feb, 2020, 05:35: PM
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