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plz solve the question
Asked by jmorakhia | 08 May, 2019, 14:23: PM
Expert Answer
Total work done by the battery in fully charging the capacitor is given by
Energy stored in the capacitor is
The final energy stored in the capacitor is half of the work done by the battery.The other half is dissipated in the resistor in the form of heat.
Energy stored in capacitor
Hence the enrgy supplied by the battery is greater than 2mJ.
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