CBSE Class 12-science Answered
Plz solve no 3
Asked by Ranjan | 29 Apr, 2018, 08:58: PM
Expert Answer
capacitance C of parallel plate capacitor = (kε0A)/d ;
k - dielectric constant ε0 - permitivity of free space, A - area of plate, d is distance between plates
C = (4×8.854×10-12×A)/(2×10-4) = 17.70 × 10-8×A Farad
Q = C×V = 17.70 × 10-8×A×2.828×1000;
Q/A = 17.70 × 10-8×2.828×1000 = 500.56 μC / m2
Answered by Thiyagarajan K | 29 Apr, 2018, 09:40: PM
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