pls. solve

Asked by  | 30th Jan, 2009, 06:11: PM

Expert Answer:

Draw the triangle as mentioned in the question.

Now consider triangles ADB and AEC.

Both are right triangles according to the information given in the question.

So,

 angle AEC= angle ADB(each is 90 degrees)

angle A = angle A ( common to both triangles)

So,

triangle AEC is similar to triangle  ADB ..(AA similarity)

So,

AE/AD=EC/DB=AC/AB ...( as corresponding sides of similar triangles are proportional)

So,

AE/AD=AC/AB

cross multiplying, we get,

AE*AB=AC*AD

Hence proved.

Note that  it's very important in such questions  to identify which triangles should you consider for similarity.The statement to be proved usually gives a hint on this  matter.

 

Answered by  | 31st Jan, 2009, 08:57: AM

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