# ICSE Class 10 Answered

**Pls answer the question on Circles Thanks.**

Asked by birpori | 04 Nov, 2018, 02:34: PM

Expert Answer

Join OD

OD = OA .....radii

so in triangle AOD

angle ODA = angle OAD = x

so angle COD = 2x......exterior angle

so in triangle COD

OD perpendicular to DC......tangent radius

angle DCB = 90-2x

now join BD

angle DBC is exterior angle of tri ABD

also angle ADB = 90, angle subtended by diameter

so angle DBC = 90 + x

Answered by Arun | 06 Nov, 2018, 09:56: AM

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