JEE Class main Answered

plese solve it in detail with step by step explanation

Asked by ashwinbalaaji30 | 18 May, 2021, 10:51: AM

Expert Answer

Given: sin^-1x + 2cos^-1x = 2pi/3

Since space sin to the power of negative 1 end exponent straight x plus cos to the power of negative 1 end exponent straight x equals straight pi over 2 rightwards double arrow sin to the power of negative 1 end exponent straight x plus 2 cos to the power of negative 1 end exponent straight x equals fraction numerator 2 straight pi over denominator 3 end fraction rightwards double arrow sin to the power of negative 1 end exponent straight x plus cos to the power of negative 1 end exponent straight x plus cos to the power of negative 1 end exponent straight x equals fraction numerator 2 straight pi over denominator 3 end fraction rightwards double arrow straight pi over 2 plus cos to the power of negative 1 end exponent straight x equals fraction numerator 2 straight pi over denominator 3 end fraction rightwards double arrow cos to the power of negative 1 end exponent straight x equals fraction numerator 2 straight pi over denominator 3 end fraction minus straight pi over 2 equals fraction numerator 4 straight pi minus 3 straight pi over denominator 6 end fraction equals straight pi over 6 rightwards double arrow straight x equals cos straight pi over 6 equals fraction numerator square root of 3 over denominator 2 end fraction

Answered by Renu Varma | 20 May, 2021, 16:02: PM

Please Login or Sign up to continue!