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Asked by ashwinbalaaji30 | 18 May, 2021, 10:51: AM
Given: sin-1x + 2cos-1x = 2pi/3
![Since space sin to the power of negative 1 end exponent straight x plus cos to the power of negative 1 end exponent straight x equals straight pi over 2
rightwards double arrow sin to the power of negative 1 end exponent straight x plus 2 cos to the power of negative 1 end exponent straight x equals fraction numerator 2 straight pi over denominator 3 end fraction
rightwards double arrow sin to the power of negative 1 end exponent straight x plus cos to the power of negative 1 end exponent straight x plus cos to the power of negative 1 end exponent straight x equals fraction numerator 2 straight pi over denominator 3 end fraction
rightwards double arrow straight pi over 2 plus cos to the power of negative 1 end exponent straight x equals fraction numerator 2 straight pi over denominator 3 end fraction
rightwards double arrow cos to the power of negative 1 end exponent straight x equals fraction numerator 2 straight pi over denominator 3 end fraction minus straight pi over 2 equals fraction numerator 4 straight pi minus 3 straight pi over denominator 6 end fraction equals straight pi over 6
rightwards double arrow straight x equals cos straight pi over 6 equals fraction numerator square root of 3 over denominator 2 end fraction](https://images.topperlearning.com/topper/tinymce/cache/d8deffe08e9159010c46bef51829d1c2.png)
Answered by Renu Varma | 20 May, 2021, 16:02: PM
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