JEE Class main Answered
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Asked by shettyatul17 | 02 Jun, 2019, 06:45: AM
Expert Answer
2a = 3b = 6-c = k (say)
Consider, 2a = k
log 2a = log k
alog 2 = log k
a = log k/log 2
Similarly b = log k/log 3 and c = -log k/log 6
Put it in the ab + bc + ca and solving it further we get
ab + bc + ca = 0
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