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Please solve how to find k=0,2,1/3
Asked by sanjaysingh.srct | 19 Sep, 2019, 12:36: PM
Expert Answer
Line x-2y+3=0 meet the axes at points A(0,3/2) and B(-3,0)
Line y=kx-1 meet the y axis at point C(0,-1)
Since the above two lines meet the axes in concyclic points
So, the above 3 points satisfies the equation of a circle given by
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