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JEE Class main Answered

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Asked by rohan1234rathor | 07 Jun, 2022, 08:20: PM
answered-by-expert Expert Answer
2x + 2y = 2
rightwards double arrow 2 to the power of straight y equals 2 minus 2 to the power of straight x
rightwards double arrow log subscript 2 space 2 to the power of straight y equals log subscript 2 open parentheses 2 minus 2 to the power of straight x close parentheses
rightwards double arrow straight y equals log subscript 2 open parentheses 2 minus 2 to the power of straight x close parentheses
rightwards double arrow straight f left parenthesis straight x right parenthesis equals log subscript 2 open parentheses 2 minus 2 to the power of straight x close parentheses
Now comma space log space straight x space is space defined space for space straight x space greater than space 0
Therefore comma space we space must space have space 2 minus 2 to the power of straight x greater than 0
straight i. straight e. space 2 greater than 2 to the power of straight x
rightwards double arrow log subscript 2 space 2 greater than log subscript 2 space 2 to the power of straight x
rightwards double arrow 1 greater than straight x
rightwards double arrow straight x greater than 1
Hence comma space the space domain space of space straight f left parenthesis straight x right parenthesis space is space left parenthesis 1 comma space infinity right parenthesis.
Answered by Renu Varma | 08 Jun, 2022, 11:49: AM
JEE main - Maths
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