NEET Class neet Answered
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Asked by Prashant DIGHE | 26 Dec, 2019, 10:36: PM
Expert Answer
if receving signal is 300 m band, its wavelength 300 m, hence frequency f = 3×108 / 300 = 106 Hz
Required capacitance C for resonance is obtained as,
LC = 1/ω2 or C = 1 / ( L ω2 ) = 1/ ( 10-3 × 4π2 × 1012 ) ≈ .025 nF
Answered by Thiyagarajan K | 27 Dec, 2019, 09:28: AM
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