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Asked by Prashant DIGHE | 26 Dec, 2019, 22:34: PM
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Maximum RMS current is obtained when the inductive impedence XL equals Capacitive impedence XC .
 
Hence net impedence Z = [ R2 - (XL - XC)2 ]1/2 = R  , where R is resistance of coil
 
If RMS current is 6A  ,  i.e.,  im = vm / R  = 6 A  , hence  resistance of coil R = vm / im = 24 V / 6 A = 4 Ω
 
when this coil connected to battery of EMF 12 V and internal resistance 4 Ω , only DC current is passing through.
 
Hence current = 12 /(4+4) = 1.5 A
Answered by Thiyagarajan K | 27 Dec, 2019, 09:19: AM

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