NEET Class neet Answered
please answer this
Asked by Prashant DIGHE | 15 Jan, 2020, 10:09: PM
Expert Answer
By neglecting VBE , i.e. Bae-to-emitter voltage, we have, IbRb = 9 V
Hence Rb = 9 V / 35 μA = (9/35) × 106 Ω = 257 kΩ
Answered by Thiyagarajan K | 16 Jan, 2020, 07:48: AM
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