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Asked by Prashant DIGHE | 28 Apr, 2020, 21:58: PM
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position vector , begin mathsize 14px style r with rightwards arrow on top equals space x space i with hat on top space plus space y space j with hat on top space equals space a left parenthesis space 1 space minus space cos omega t space right parenthesis space space i with hat on top space plus space a space sin omega t space space j with hat on top space end style
Hence x coordinate is given by,  x(t) = a [ 1- cos(ωt) ] 
 
y coordinate is given by,  y(t) = a sin(ωt)
 
from above equation, we get,  x2 + y2 = a2 [ 1 - cos (ωt) ]2 + a2 sin2 (ωt) = 2a2 [ 1 - cos(ωt) ] = 2a x
 
Hence the trajectory is given by, x2 + y2 - 2ax = 0 
 
The above equation is equation of a circle with centre ( a, 0 ) and radius a
 
Answered by Thiyagarajan K | 28 Apr, 2020, 23:17: PM

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