NEET Class neet Answered
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Asked by Prashant DIGHE | 03 Mar, 2020, 22:00: PM
Option (2) is correct.
Given:
For bulb A,
Volume, VA = 100 ml
Pressure, =PA
For Bulb B,
Volume, =VB
Pressure, PB = ![40 over 100 straight P subscript straight A](https://images.topperlearning.com/topper/tinymce/cache/503a51628ee12280be9912be4e052a8f.png)
![40 over 100 straight P subscript straight A](https://images.topperlearning.com/topper/tinymce/cache/503a51628ee12280be9912be4e052a8f.png)
Using Boyle's law,
PAVA = PBVB
PA × 100 =
× VB
![40 over 100 straight P subscript straight A](https://images.topperlearning.com/topper/tinymce/cache/503a51628ee12280be9912be4e052a8f.png)
VB = ![fraction numerator 100 over denominator 0.4 end fraction](https://images.topperlearning.com/topper/tinymce/cache/46255f9d93c8a10b7f1ae541fb0aab41.png)
![fraction numerator 100 over denominator 0.4 end fraction](https://images.topperlearning.com/topper/tinymce/cache/46255f9d93c8a10b7f1ae541fb0aab41.png)
VB = 250 ml
Before opening stopcock, volume of gas in bulb B must be (250-100) = 150 ml
Answered by Varsha | 04 Mar, 2020, 09:47: AM
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