NEET Class neet Answered
please answer this
Asked by Prashant DIGHE | 10 Jan, 2020, 10:07: PM
Expert Answer
decay constant λ = ln2 / T1/2 = 0.693 / 1386 = 5×10-4 s-1
Radioactivity equation, N = No e-λt
Fraction of undecayed sample after 80 s = N / No = exp( - 5 × 10-4 × 80 ) = 0.96
Hence fraction of number of nuclei that has decayed in initial 80 s = 1 - 0.96 = 0.04
Hence fraction of number of nuclei ( expressed in % ) that has decayed in initial 80 s = 4 %
Answered by Thiyagarajan K | 10 Jan, 2020, 10:56: PM
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