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Asked by Prashant DIGHE | 12 Jan, 2020, 21:20: PM
answered-by-expert Expert Answer
It is assumed that given power in the question is thermal power
 
Energy produced by reactor in one day = Power(W) × time(s) =  106 × 24 × 3600 J = 8.64 × 1010 J
 
Energy released per fission = 200 MeV = 200 × 106 × 1.602 × 10-19 J = 3.204 × 10-11 J
 
Number of fission reactions to produce 1 MW power in 1 day = ( 8.64 × 1010 / 3.204 × 10-11 ) ≈ 2.7 × 1021 
 
Hence required number of 235U atoms = 2.7 × 1021
 
Required amount of 235U in mass = 2.7 × 1021 × [ 235 / ( 6.02 × 1023) ] = 1.05 g
Answered by Thiyagarajan K | 13 Jan, 2020, 10:16: AM

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