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NEET Class neet Answered

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Asked by Prashant DIGHE | 14 Jan, 2020, 10:09: PM
answered-by-expert Expert Answer
Activity of radioactive sample after 3 half life = c × 2-3 = 0.125c
 
Activity found in the leftover sample = c/10 = 0.1c
 
Activity is proportional to volume
 
Volume of remaining sample = (0.1c / 0.125 c) × 100 cm3 = 80 cm3
Answered by Thiyagarajan K | 15 Jan, 2020, 07:28: AM
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