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Please answer the following question with explanation
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Asked by deepakudgiri29 | 02 May, 2019, 23:08: PM
answered-by-expert Expert Answer
Change in entropy ΔS = entropy change for ice to melt + entropy change when heated from 0°C to 40°C
 
=  (ΔQ/Ti) +  m×Cp×ln( Tf / Ti)
 
ΔQ = latent heat of fusion of ice = 80 cal/g
 
Ti = ice temperature = 273 K , Tf = final temperature = 313 K
m = mass of ice = 1 g
 
CP = Specific heat of ice = 1 cal/( g °C )
 
ΔS = (80/273) + 1×1×0.1366 ≈ 0.42 cal/°C
Answered by Thiyagarajan K | 03 May, 2019, 14:22: PM

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