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Asked by jain.pradeep | 04 Feb, 2020, 06:41: PM
answered-by-expert Expert Answer
We have given,
 
straight U presubscript 92 presuperscript 238 rightwards arrow with blank on top Pb presubscript 92 presuperscript 206
An ore of U236 found to contain U236 and Pb206 in the weight ratio of 1:0.1.
Half life period of U236 = 4.5×109 years
 
straight N subscript 0 equals 1 over 238 plus fraction numerator 0.1 over denominator 206 end fraction space equals space 46.85 cross times 10 to the power of negative 4 end exponent mole

straight N equals 1 over 238 equals 42.0 cross times 10 to the power of negative 4 end exponent mole

straight lambda space equals fraction numerator 0.693 over denominator 4.5 cross times 10 to the power of 9 end fraction equals 1.54 cross times 10 to the power of negative 9 end exponent space years to the power of negative 1 end exponent

As space we space know comma

straight t equals fraction numerator 2.303 over denominator 1.54 cross times 10 to the power of negative 10 end exponent end fraction log fraction numerator 46.85 cross times 10 to the power of negative 4 end exponent over denominator 42.0 cross times 10 to the power of negative 4 end exponent end fraction

straight t equals 7.097 cross times 10 to the power of 8 space year

Answered by Ramandeep | 05 Feb, 2020, 12:38: PM
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