Request a call back

Pl ans
Figure shows the two identical circular loops of radius R, one having linear charge density +λ C/m and
other one having charge density -λ C/m are placed so that centres of loop are ata distance (√3 R ) apart.

Electric field is required at centre point O due to both charged loops.

Let us consider small line elements of length dl as shown in the top figure on both loops.
Their respective charges are +λdl and -λdl . Distance between centre point O and these line elements is
calculated as ( 1.323 R )

As seen from figure , electric field at point due to the line elements +λdl and -λdl gives resultant field field along the direction AO

Figure given at bottom shows even if we consider line elements in opposite direction, net resultant field is along the direction AO.

Magnitude of electric field due to each line element ,  | E+ | = | E- | = ( λdl )/ [ (4πεo ) (1.323 R)2 ]

Hence Net resultant field due to both the loops = 2 { ( 2 π R λ )/ [ (4πεo ) (1.323 R)2 ] } cos 49
Answered by Thiyagarajan K | 07 Dec, 2019, 09:44: AM

## Concept Videos

CBSE 12-science - Physics
Asked by goswamideepak16492 | 12 Jun, 2024, 10:18: AM
CBSE 12-science - Physics
CBSE 12-science - Physics
Asked by rahuldevgayen4 | 10 Jun, 2024, 02:58: PM
CBSE 12-science - Physics
Asked by yy8965818 | 07 Jun, 2024, 08:36: PM
CBSE 12-science - Physics
Asked by vaidehi262008 | 05 Jun, 2024, 10:09: PM
CBSE 12-science - Physics