on the basis of crystal field theory, why co(iii) forms paramagnetic octahedral complexes with weak field ligands but diamagnetic octahedral complexes with strong field ligands?
 

Asked by bharti2k5 | 9th Jan, 2016, 05:58: PM

Expert Answer:

With weak field ligands; ΔO < p, the electronic configuration of Co (III) will be t42g e2g and it has 4 unpaired electrons and hence is paramagnetic.

With strong field ligands, ΔO > p, the electronic configuration of Co(III) will be t62g e0g . It has no unpaired electrons and hence is diamagnetic.

Answered by Prachi Sawant | 10th Jan, 2016, 04:07: PM