JEE Class main Answered
There are 8 questions. But only one question per posting is allowed.
Hence only first two questions are answered.
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qn, # 1
4x + i ( 3x-y) = 3 - i 6
equating real and imaginary parts , we get
4x = 3 and (3x-y) = -6
hence we get , x= 3/4
y = 3x+6 = 3 (3/4) + 6 = 33/4
x= 3/4 and y = 33/4
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qn. #2
( x4 + 2 x i ) - ( 3 x2 + i y ) = ( 3 - 5 i ) + [ 1 + (2 y) i ]
( x4 - 3 x2 ) + ( 2x - y ) i = 4 + ( 2y - 5 ) i
we get
( x4 - 3 x2 ) = 4 ..............................(1)
(2x-y) = ( 2y -5 ) ..........................(2)
From eqn.(1),
( x4 - 3 x2 ) = x2 ( x2 - 3 ) = 4
from above expression we get x2 = 4 , x = +2 or -2
From eqn.(2) ,
(2x-y) = ( 2y -5 )
3y = 2x + 5
if x =2 , then 3y = 9 or y = 3
if x=-2 , then 3y = 1 or y = 1/3
hence we get
x=2 , y = 3 or x=-2 , y = 1/3