Nitin walks at 3/4 of his usual speed and reaches home 10 minutes late find the usual time taken by him to reach home?

 

Asked by Sidramairaj6166 | 7th Aug, 2019, 05:14: PM

Expert Answer:

begin mathsize 16px style Let space the space usual space speed space of space Nitin space equals space straight x space km divided by hrs
Speed space equals space Distance over Time
Accroding space to space the space conditions space in space the space question comma space we space get
straight x space equals space straight d over straight t space space space.... space left parenthesis 1 right parenthesis
3 over 4 straight x space equals space fraction numerator straight d over denominator straight t space plus space 10 end fraction space space space... space left parenthesis 2 right parenthesis
Substitute space the space value space of space straight x space from space left parenthesis 1 right parenthesis space space to space left parenthesis 2 right parenthesis comma space we space get

3 over 4 cross times straight d over straight t equals space fraction numerator straight d over denominator straight t space plus space 10 end fraction
rightwards double arrow 3 straight d left parenthesis straight t space plus space 10 right parenthesis space equals space 4 dt
rightwards double arrow 3 dt space plus space 30 straight d space equals space 4 dt
rightwards double arrow dt space equals space 30 straight d
rightwards double arrow space space straight t space space equals space 30


end style
Therefore the usual time taken by Nitin is 30 mins.

Answered by Yasmeen Khan | 7th Aug, 2019, 06:05: PM