CBSE Class 12-science Answered
Maximize Z=4x+9y, subject to constraints x?0,y?0,x+5y?200,2x+3y?134
The answer given in the book is: Maximum Z=382 when x=10 and y=38
Asked by Manoj | 19 Jun, 2013, 07:14: PM
Expert Answer
if you draw a graph for the given 4 constraint equation -- x?0,y?0,x+5y?200,2x+3y?134 and identify the polygon enclosed by the equations, you will find that its is a quadrilateral, with A(0,0); B(67,0); C(10,38); D(0,40)
Now since its an enclosed area, the maximum value of Z should be at one of the vertices.
hence, at A(0,0); Z = 4(0) + 9(0) = 0
at B(67,0); Z = 4(67) + 9(0) = 268
at C(10,38); Z = 4(10) + 9(38) = 382
at D(0,40); Z = 4(0) + 9(40) = 360
So, the maximum value of Z is at C(10,38) and the value is 382.
Answered by | 23 Jun, 2013, 07:36: AM
Concept Videos
CBSE 12-science - Maths
Asked by gargisha381 | 26 May, 2022, 12:24: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by ABHILASHA | 20 Apr, 2021, 12:07: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Sunita | 27 Oct, 2020, 12:07: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 01 Sep, 2014, 01:19: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 29 Jul, 2016, 10:09: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 01 Sep, 2014, 02:00: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 01 Sep, 2014, 02:43: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 01 Sep, 2014, 02:46: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 29 Jul, 2016, 09:56: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 18 Sep, 2014, 02:12: PM
ANSWERED BY EXPERT