kindly give solution to the question in the image.

Consider angle PRQ = x

so PQR = x ......iso triangle

angle QPR = 180 - 2x

now, for QT || to PR

we need to prove 

angle PQT = angle QPR

lets consider this is equal

angle PQT = angle QPR = angle SQT= 180 - 2x

now,

angle PQT + angle SQT + angle PQR = 180....angles in st. line

180-2x + 180 - 2x + x = 180

so, x= 60

that means triangle PQR should be equilateral, so data is missing in the question