Kindly explain your answer.

 

Asked by Varsneya Srinivas | 9th Feb, 2018, 09:07: AM

Expert Answer:

begin mathsize 16px style tan to the power of negative 1 end exponent straight a plus tan to the power of negative 1 end exponent straight b plus tan to the power of negative 1 end exponent straight c
equals tan to the power of negative 1 end exponent space open parentheses fraction numerator straight a plus straight b over denominator 1 minus ab end fraction close parentheses plus tan to the power of negative 1 end exponent straight c space space space space space space space space space space space space space tan to the power of negative 1 end exponent straight x plus tan to the power of negative 1 end exponent straight y equals tan to the power of negative 1 space end exponent open parentheses fraction numerator straight x plus straight y over denominator 1 minus xy end fraction close parentheses
equals tan to the power of negative 1 end exponent space open parentheses fraction numerator fraction numerator straight a plus straight b over denominator 1 minus ab end fraction plus straight c over denominator 1 minus fraction numerator straight a plus straight b over denominator 1 minus ab end fraction cross times straight c end fraction close parentheses
After space simplifying space we space get
equals tan to the power of negative 1 end exponent space open parentheses fraction numerator straight a plus straight b plus straight c minus abc over denominator 1 minus ac minus bc end fraction close parentheses
According space to space the space question space
straight a plus straight b plus straight c minus abc equals 0
equals tan to the power of negative 1 end exponent left parenthesis 0 right parenthesis
equals straight pi end style

Answered by Sneha shidid | 9th Feb, 2018, 09:35: AM