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CBSE Class 12-science Answered

It is about how the properties are used.
Asked by | 02 Jul, 2013, 09:43: AM
answered-by-expert Expert Answer
Please ask one question at a time. The answer to your first question is as follows:
 
tan-1 (cosx /1-sinx)
= tan-1 ( { cos2 (x/2) - sin (x/2) } / [cos(x/2) - sin(x/2) ]2 )
= tan-1 ( { cos(x/2) + sin(x/2) } [cos(x/2) - sin(x/2) ] )
Divide the Numerator and Denominator by cos(x/2)
= tan-1( { 1 + tan(x/2) } / [ 1- tan(x/2) ] )
= tan-1( { tan?/4 + tan(x/2) } / [ 1-tan?/4 tan(x/2) ] )
= tan -1 ( tan( ?/4 + (x/2) ) )
= ?/4 + (x/2)
Answered by | 06 Jul, 2013, 11:39: PM

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