CBSE Class 10 Answered
in triangle ABC is a right triangle right angle B and sin c is equal to 12 by 25 find the value of sin A cos c minus cos A sin c
Asked by sandipmukherjee16536 | 14 Sep, 2023, 20:16: PM
![](https://images.topperlearning.com/topper/tinymce/imagemanager/files/64e2f9f5fa813f5f1c8679185336a9726509bb8c6074b2.36104989f1.png)
If sinC = AB/ AC = 12/25 , then side BC = ![begin mathsize 14px style square root of A C squared minus A B squared end root space equals space square root of 25 squared minus 12 squared end root space equals space 21.93 end style](https://images.topperlearning.com/topper/tinymce/cache/1fefecceb7e2c70ca9f94acd15f9573c.png)
![begin mathsize 14px style square root of A C squared minus A B squared end root space equals space square root of 25 squared minus 12 squared end root space equals space 21.93 end style](https://images.topperlearning.com/topper/tinymce/cache/1fefecceb7e2c70ca9f94acd15f9573c.png)
sinA = 21.93/25 , cosA = 12/25 and cosC = 21.93/25
sinA cosC - cosA sinC = (21.93 / 25 ) ( 21.93 /25) - (12/25) (12/25) = (1/25)2 [ (21.93)2 - (12)2 ]
sinA cosC - cosA sinC = (1/25)2 [ 33.93 × 9.93 ] = 0.539
Answered by Thiyagarajan K | 19 Sep, 2023, 20:57: PM
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