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in this question the 4 s e- gets backpaired to 3d even though no. of WFL>no. of SFL. Does it mean only 1 SFL is requred to backpair e- even when sfl
Asked by aaryamanmodern | 17 Jul, 2023, 08:52: AM
Expert Answer
Dear student,
The final result of pairing or not pairing kdepends upon the total strength of strong ligands which can vary in each case. Different ligands have different strength.
In this case 1 NO ligand is sufficient to nullify the effect of 5 H2O ligands which results into backpairing.
Answered by | 18 Jul, 2023, 11:04: PM
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