CBSE Class 9 Answered
In fig., O is the center of the circle of
radius 5 cm. OP 
AB, OQ
CD, AB||CD. 
= 6 cm, 
= 8 cm.
Determine PQ.
AB, OQ
CD, AB||CD. = 6 cm, = 8 cm.
Determine PQ.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
Since the perpendicular from the center of the circle to a chord bisects the chord.
P and Q are the mid points of AB and CD
In right triangles OAP and OCQ, we have
OA2 = OP2 + AP2 and OC2 = OQ2 + CQ2
52 = OP2 + 32 and 52 = OQ2 + 42
OP2 = 52 - 32 and OQ2
= 52 - 42
OP2 = 16 and OQ2 = 9
OP
= 4 and OQ = 3
PQ = OP
+ OQ = 4 + 3 = 7 cm
Answered by | 04 Jun, 2014, 03:23: PM
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